w^2-w(w-3)=12(1+w)

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Solution for w^2-w(w-3)=12(1+w) equation: 



w^2-w(w-3)=12(1+w)

We move all terms to the left:

w^2-w(w-3)-(12(1+w))=0

We add all the numbers together, and all the variables

w^2-w(w-3)-(12(w+1))=0

We multiply parentheses

w^2-w^2+3w-(12(w+1))=0



We calculate terms in parentheses: -(12(w+1)), so:

12(w+1)

We multiply parentheses

12w+12

Back to the equation:

-(12w+12)



We add all the numbers together, and all the variables

3w-(12w+12)=0

We get rid of parentheses

3w-12w-12=0

We add all the numbers together, and all the variables

-9w-12=0

We move all terms containing w to the left, all other terms to the right

-9w=12

w=12/-9

w=-1+1/3

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